RO-AN
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The ANR bank contains many sets with original names and codes, including navigation, safety and equipment topics. Select a module by name or use question search.
“ANR — RO-AN” contains 115 questions across 1 collection.
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Determinati pierderea de putere politropica specifica, in cazul defectarii condensorului pentru o turbina cu abur. Date cunoscute: presiunea initiala p1=40[bar]; temperatura initiala t1=500[grade C]; titlul pentru destinderea izentropica x ad=0,83; randamentul intern 0,85; cresterea de presiune 0,4[bar].
One correct answer
Determinati cantitatea de condens necesar pentru pulverizat in camera de amestec a unei instalatii de reglare a temperaturii aburului supraincalzit izobar. Date cunoscute: presiunea nominala a aburului p= 5 MPa, temperatura de supraincalzire reglata t si=500 grade C, presiunea de condensare P cd=0,5 bar, debitul de abur 10 to/h, cresterea de temperatura 50 grade C...
One correct answer
Calculati randamentul unei caldari cu supraincalzitor intermediar izobar pentru care se cunosc urmatoarele date: presiunea de vaporizare p1=60 bar, presiunea intermediara p2=0,25 p1, temperaturile de supraincalzire t si= 400 grade C, temperatura apei de alimentare taa=tsat-100 grade C, debitul nominal de abur D=20 to/h, randamentul vaporizatorului de 55%, puterea calorifica inferioara a combustibilului Qi=40MJ/kg.Destinderea in prima treapta a turbinei se considera adiabata...
One correct answer
Determinati pierderea de putere in cazul defectarii supraincalzitoarelor pentru o turbina in doua trepte cu supraincalzire intermediara. Date cunoscute: debit nominal D=25[t0/h]; presiune nominala p1=5[mPa]; presiune de condensatie p cd=0,15[bar]; raportul de scadere a presiunii 0,25; temperaturi de supraincalzire t si=550 [grade C].
One correct answer
Determinati parametrii initiali ai aburului de la o turbina cu urmatoarele date cunoscute:debitul specific (destindere politropica) d pol= 5[kg/kwh]; presiunea de condensatie p2= 20[kPa]; titlul aburului (destindere izentropica) x= 0,8; randamentul intern 0,8.
One correct answer
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